Register

THE POLICE USE A SPEED GUN TO MONITOR ONE PART OF A HIGHWAY. DURING ONE HOUR , 60 OUT OF 25 CARS WERE TRAVELING ABOVE THE SPEED LIMT. WHAT PERCENT OF THE CARS WERE TRAVELING ABO…

THE POLICE USE A SPEED GUN TO MONITOR ONE PART OF A HIGHWAY. DURING ONE HOUR , 60 OUT OF 25 CARS WERE TRAVELING ABOVE THE SPEED LIMT. WHAT PERCENT OF THE CARS WERE TRAVELING ABO…
185k views
2 votes
THE POLICE USE A SPEED GUN TO MONITOR ONE PART OF A HIGHWAY. DURING ONE HOUR , 60 OUT OF 25 CARS WERE TRAVELING ABOVE THE SPEED LIMT. WHAT PERCENT OF THE CARS WERE TRAVELING ABOVE THE SPEED LIMIT?

User Vijay DJ
by
8.7k points

2 Answers

2 votes
24% because 6/25 is = .24 which is 24%
User Rob Cameron
by
8.5k points
3 votes
how do 60 out of 25 speed? is it supposed to be 25 out of 60 cars?

User Kerstomaat
by
8.6k points
← Prev Question Next Question →

Related questions

User Dharan
asked Oct 28, 2024 32.8k views
Compute limt h→0 f(3 h)−f(3) h where f=x² (a) 1 (b) 2 (c) 3 (d) 6
Dharan asked Oct 28, 2024
by Dharan
8.0k points
1 answer
4 votes
32.8k views
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!