118k views
5 votes
Find the perimeter of \triangle ABC△ABC with vertices A(1, 1), B(7, 1), and C(1, 9).

2 Answers

4 votes
the perimeter of the triangle, will be the lengths of all segments,
making it up, so.. find the lengths of segments AB, BC and CA,
and sum them up

\textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &A({{ 1}}\quad ,&{{ 1}})\quad % (c,d) &B({{ 7}}\quad ,&{{ 1}})\\ &B({{ 7}}\quad ,&{{ 1}})\quad % (c,d) &C({{ 1}}\quad ,&{{ 9}})\\ &C({{ 1}}\quad ,&{{ 9}})\quad % (c,d) &A({{ 1}}\quad ,&{{ 1}})\\ \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
User Enzuguri
by
6.6k points
6 votes
Not totally sure but the answer might be 14 units
User FunctorSalad
by
7.0k points
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