Question

A lawyer owns 4 pairs of pants, 5 dress shirts and 6 ties. How many days can the lawyer go without wearing the same combination of three items?

Answer 1

4 ways to wear all pants
5 ways to wear shirts
6 ways to wear ties
4*5*6=120 different combos
think of it like this

eample
2 pairs of pants and 3 pairs of shirts
a,b are the pants, and c,d,e are the shirts
the ways are below
ac
ad
ae
bc
bd
be
2*3=6, 6 ways

answer is 120 days

Answer 2

I believe that to calculate this, you do 4x5x6 and then divide it by 3, to get 40