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5 votes
A lawyer owns 4 pairs of pants, 5 dress shirts and 6 ties. How many days can the lawyer go without wearing the same combination of three items?

2 Answers

3 votes
4 ways to wear all pants
5 ways to wear shirts
6 ways to wear ties
4*5*6=120 different combos
think of it like this

eample
2 pairs of pants and 3 pairs of shirts
a,b are the pants, and c,d,e are the shirts
the ways are below
ac
ad
ae
bc
bd
be
2*3=6, 6 ways

answer is 120 days
User Mike Izbicki
by
8.5k points
2 votes
I believe that to calculate this, you do 4x5x6 and then divide it by 3, to get 40
User Ggilberth
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8.5k points