Question

QUESTION 2

Given the reaction, PCl3 + Cl2 Imported Asset PCl5, if 3.00 moles of Cl2 are used, then how many moles of PCl5 are made?

6.00 moles

5.00 moles

3.00 moles

1.00 mole
3 points Save Answer
QUESTION 3

Given the balanced equation, Fe2O3 + 3 CO Imported Asset 2 Fe + 3 CO2, what is the molar ratio of CO to CO2?

3:3

3:1

3:2

1:3
3 points Save Answer
QUESTION 4

Using the equation, 4Fe + 3O2 Imported Asset 2Fe2O3, if 96.0 g of oxygen react, what mass of iron was oxidized?

32.0 g

96.0 g

167 g

223 g
3 points Save Answer
QUESTION 5

Using the equation, C5H12 + 8O2 Imported Asset 5CO2 + 6H2O, if 10 moles of carbon dioxide are produced, how many moles of pentane (C5H12) would need to be supplied?

2 moles

0.5 mole

5 moles

10 moles
3 points

Answer 1

2) Here, 1 Cl2 gives 1 PCl5, so their molar ratio = 1:1
So, if 3 moles of Cl2, are used it will produce 3 moles of PCl5.

In short, Your Answer would be Option C) 3.00 moles

3) Molar ratio = 3 / 3 = 1 : 1

4) As you can see in the reaction, for each that reacts, two are created.
Oxygen moles = 96/16 = 6
So, iron moles = 6/3 * 2 = 4 moles
4 * 55.8 = 223 g [ 55.8 = molar mass of Iron ]

In short, Your Answer would be Option D

5) Molar ratio of C5H12 to CO2 is 1 : 5
So, if 10 CO2 are produced, it needs = 10 / 5 = 2 moles of C5H12

In short, Your Answer would be Option A) 2 moles

Hope this helps!

Answer 2

Step-by-step explanation:

1) Answer 2:
`PCl_3+Cl_2\rightarrow PCl_5`

According to reaction, 1 mol of chlorine gas gives 1 mol of
`PCl_5]`

Then, 3.00 moles of chlorine gas will give :

`(1)/(1)* 3.00 mol = 3.00 \text{moles of }PCl_5`

3.00 moles of
`PCl_5` are made.

2) Answer 3:
`Fe_2O_3 + 3 CO\rightarrow 2Fe + 3 CO_2`

Molar ratio is defined ratio of moles of two different substances.

Moles of carbon monoxide gas = 3 mol

Moles of carbon dioxide gas = 3 mol

Molar ratio of
`CO to CO_2=(3 mol)/(3 mol)=3:3 = 1:1`

Molar ratio of
`CO to CO_2` is 3:3.

3) Answer 4:
`4Fe_2O_3 +3O_2\rightarrow 2Fe_2O_3`

Moles of oxygen gas =
`(96.0 g)/(32 g/mol)=3 mol`

According to reaction 3 moles of oxygen gas reacts with 4 mol of iron metal.

Then mass of 4 mol of iron metal :4 mol × 55.85 g/mol =223.4 g≈223 g

223 grams of iron was oxidized.

4) Answer 5;
`C_5H_(12) + 8O_2\rightarrow 5CO_2 + 6H_2O`

According to reaction , 5 moles of carbon dioxide are produced by 1 mol of pentane.

Then 10 moles of carbon dioxide will be produced by:

`(1)/(5)* 10 mol=2 mol` of pentane.

2 moles of pentane would need to be supplied.