Question

The factored form of 4a3b5 − 16a5b2 + 12a2b3

Answer 1

4a3b5 − 16a5b2 + 12a2b3 = 4 * a^2 * b^2 * ( a*b^3 - 4 * a^3 * + 3 * b^3)

Answer 2

`4a^2b^2(ab^3 -4a^3+3b)`

Explanation:

Given :
`4a^3b^5 -16a^5b^2+12a^2b^3`

To Find: Find factored form.

Solution:

`4a^3b^5 -16a^5b^2+12a^2b^3`

Take 4 as common

`4(a^3b^5 -4a^5b^2+3a^2b^3)`

Now take
`a^2` as common

`4a^2(ab^5 -4a^3b^2+3b^3)`

Now take
`b^2` as common

`4a^2b^2(ab^3 -4a^3+3b)`

Hence The factored form of
`4a^3b^5 -16a^5b^2+12a^2b^3` is
`4a^2b^2(ab^3 -4a^3+3b)`