Question

What is the energy of a 933 nm wave?

Answer 1

E=hc/l

E=

E=(6.626 x 10-34 J s)(3.0 x 108m/s )=2.88 x 10-19J6.90 x 10-7m

Answer 2

Answer:
`0.02130* 10^(-17)Joules`

Step-by-step explanation:

`E=(hc)/(\lambda)`

E= energy

h = Planck's constant =
`6.626* 10^(-34)Js`

c = speed of light =
`3* 10^8ms^(-1)`

`\lambda` = Wavelength of radiation = 933 nm =
`933* 10^(-9)m`

Now put all the given values in this formula, we get

`E=(6.626* 10^(-34)Js* 3* 10^8ms^(-1))/(933* 10^(-9)m)`

`E=0.02130* 10^(-17)Joules`

Thus energy of a 933 nm wave is
`0.02130* 10^(-17)Joules`