Question

Solve the system of equations.

2x+3y-z=2
x+y-z=2
x-3y+z=10
what is the value of y?
please help i really need it

Answer 1

pick 1 value to eliminate in 2 equations
let's eliminate z

add last equation to first one

2x+3y-z=2
x-3y+z=10 +
3x+0y+0z=12

3x=12
x=4
that's nice
sub that in last 2 equations and minus 4 from both sides

y-z=-2
-3y+z=6
add them

y-z=-2
-3y+z=6 +
-2y+0z=4

-2y=4
divide -2
y=-2


y=-2

Answer 2

The value of y is -2. Also, x= 4, z=0.