Answer:
-14.1 kJ
Explanation:
We need the specific heat of water, which is 4.184 J/g-K. It means that 4.184 Joules of energy will raise 1 gram of water by 1 degree Kelvin. It also means that removing 4.184 Joules of energy will lower the temperature of 1 gram of water by 1 degree Kelvin.
We want to lower the temperature by 15 degrees C (-15C). That is also -15K. We have 225 grams of water.
This can be used in the equation q = mc(T2 - T1),
where q is the heat, or energy, m is the mass, c is the specific heat, and (T2-T1) is the temperature change, in Kelvin.
q = mc(T2 - T1)
q = (225g)(4.184 J/g-K)(10K - 25K)
q = (225g)(4.184 J/g-K)(-15K)
q = -14121 J or -14.1 kJ
It is negative because heat is leaving the system.