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A chef bought some green and red peppers. she bought 18 green peppers, which was 3/4 the total number. how many red peppers did she buy? how many peppers did she buy altogether?

1 Answer

6 votes
Answer: She bought 6 (six) red peppers. She bought 24 peppers altogether.
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Step-by-step explanation:
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Let "y" = the total number of peppers.

(3/4)y = 18 = number of green peppers.

y = 1y = (4/4)y = total number of peppers.

So (4/4)y − (3/4)y = (1/4) y = number of red peppers.
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If, (3/4)y = 18; solve for "y" ;
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→ Given: (3/4)y = 18 ;
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→ Multiply EACH side of the equation by "4"; to get rid of the fraction;
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→ 4* (3/4)y = 18 * 4 ;
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→ 3y = 72 ;
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Divide EACH side of the equation by "3" ; to isolate "y" on one side of the equation; and to solve for "y" ;
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→ 3y / 3 = 72 / 3 ;
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→ y = 24 ;
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So, the total number of peppers = y = 24 peppers.
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We are given the number of green peppers = 18 green peppers.
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The number of red peppers = 24 − 18 = 6 red peppers.
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Also, the number of red peppers should equal: (1/4)*y ; which should equal: "6". (1/4)*y = (1/4)*24 =? 6 ? Yes! So, there are 6 red peppers.
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Answer: She bought 6 (six) red peppers. She bought 24 peppers altogether.
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