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26 votes
PLEASE HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!

1. The quadratic function f(x) has roots of −4 and 2 and point (1, −5) lies on f(x). What is the equation of f(x)?

f(x) = (x − 2)(x + 4)
f(x) = (x − 2)(x − 4)
f(x) = 4(x − 2)(x + 4)
f(x) = 4(x − 2)(x − 4)


2. What is the standard form of the equation of a quadratic function with roots of 2 and −5 that passes through (1, −3)?

y = −0.5x2 + 1.5x − 5
y = −0.5x2 + 1.5x + 5
y = 0.5x2 + 1.5x − 5
y = 0.5x2 + 1.5x + 5

User Madsongr
by
2.5k points

1 Answer

21 votes
21 votes

Answer: For 1 it is A - f(x)=(x-2)(x+4) and for 2 it is C - y = 0.5x^2 + 1.5x − 5

Explanation:

Just use Desmos

User Rasmus Franke
by
3.2k points