Question

How many atoms are in 4.00 moles of helium?

Answer 1

Number of atoms in 4.00 moles of helium =
`2.4092* 10^(24)`

Step-by-step explanation:

Avogadro’s number represent the number of the constituent particles which are present in one mole of the substance. It is named after scientist Amedeo Avogadro and is denoted by
`N_0`.

Avogadro constant:-

`N_a=6.023* 10^(23)`

Thus,

1 mole of helium contains
`6.023* 10^(23)` atoms

So,

4.00 moles of helium contains
`4.00* 6.023* 10^(23)` atoms

Number of atoms in 4.00 moles of helium =
`2.4092* 10^(24)`

Answer 2

Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles.

4 mol He ( 6.022 x 10^23 atoms / mole ) = 2.4088 x 10^34 atoms He