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If f(x)=2x^2-5 and g(x)=3x+3 find (f-g)(x)

2 Answers

6 votes

(f-g)(x) = 2x^2 - 5 - (3x+3)

(f-g)(x) = 2x^2 - 5 - 3x - 3

(f-g)(x) = 2x^2 - 3x -8

User Nishantha
by
6.3k points
4 votes

Answer:

(f-g)(x)= 2x^2-3x - 8

Explanation:

If f(x)=2x^2-5 and g(x)=3x+3 find (f-g)(x)

(f-g)(x)= f(x) - g(x)

LEts subtract f(x)- g(x). plug in given f(x) and g(x)

Replace f(x) with 2x^2 -5 and g(x) with 3x+3

(f-g)(x)= f(x) - g(x) = (2x^2 -5) - (3x+3)

We have negative sign in between , distribute negative inside the second parenthesis

(f-g)(x)= 2x^2 -5 -3x - 3

Now combine like terms

(f-g)(x)= 2x^2-3x - 8

User Behrouz Bakhtiari
by
6.7k points