Question

The fast server in women's tennis is Venus Williams, who recorded a serve of 130  mi

/h  (209  km /h ) in 2007.  If her racket pushed on the ball for a distance of 0.15 m, what was the average acceleration of the ball during her serve?

Answer 1

use the formulav^2 = u^2 + 2*a*swhere v is the final velocity of the ballu is the initial velocity of the balls is the displacement of the balla is the acceleration
Givenv=130u=0s=0.1a=?
130^2 = 0^2 + 2a(0.1)solve for a
a = 84500 m/s2