Question

A plane rises from take-off and flies at an angle of 8° with the horizontal runway. When it has gained 850 feet, find the distance to the nearest foot, the plane has flown.

850 ft

The plane has flown approximately ___ feet. (Round to the nearest foot.)

Answer 1

`C\approx 5748.2feet`

Explanation:

From the question we are told that

Angle of elevation
`\thata=8 \textdegree`

Height of plane
`H=850feet`

Generally the equation for the Distance flown is given by

`C=(H)/(sin \theta)`

`C=(800)/(sin8)`

`C=5748.237227`

`C\approx 5748.2feet`

Therefore Distance flown is

`C\approx 5748.2feet`