Question

In the circle, AB= 34, BC = 12 and CD= 8

Answer 1

the answer is A. x=61

Answer 2

Option A. x = 61

Explanation:

If two secants are intersecting each other on a point outside the circle then by theorem of intersecting secants

(x + CD)×CD = AC×BC

(x + CD)×CD = (AB + BC) × BC

Here AB = 34, BC = 12, and CD = 8

(x + 8) × 8 = (34 + 12) × 12

8x + 64 = 46×12 = 552

8x = 552 - 64 = 488

x = 488 ÷ 8

x = 61

Therefore option A. x = 61 will be the answer.