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In the circle, AB= 34, BC = 12 and CD= 8

In the circle, AB= 34, BC = 12 and CD= 8-example-1
User Tardate
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2 Answers

4 votes
the answer is A. x=61
User Ovnia
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6.4k points
6 votes

Answer:

Option A. x = 61

Explanation:

If two secants are intersecting each other on a point outside the circle then by theorem of intersecting secants

(x + CD)×CD = AC×BC

(x + CD)×CD = (AB + BC) × BC

Here AB = 34, BC = 12, and CD = 8

(x + 8) × 8 = (34 + 12) × 12

8x + 64 = 46×12 = 552

8x = 552 - 64 = 488

x = 488 ÷ 8

x = 61

Therefore option A. x = 61 will be the answer.

User Sande
by
6.6k points
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