73.3k views
2 votes
How do you isolate 2x-y+8=0?

2 Answers

4 votes
The best way to find the angular and linear coefficient is by assembling the reduced equation:

2x - y + 8 = 0
- y = - 2x - 8 .(- 1)
y = 2x + 8

The angular coefficient is the value that accompanies the X and the coefficient is the value that comes alone.

Angular Coefficient: 2
Linear Coefficient: 8

If you want to find the values ​​X and Y, we have:

2x - y + 8 = 0
2(x - 8) = y
x - 8 = 2
x = 2+8
x = 10

2x - y + 8 = 0
2*10 - y + 8 = 0
20 - y = - 8
- y = - 8 - 20
- y = - 28 .(-1)
y = 28

Confirm that the solution is correct:
2x - y + 8 = 0
2*(10) - 28 + 8 = 0
20 - 28 = -8
- 8 = - 8 (TRUE)





I hope I have helped!

User Tafari
by
8.1k points
3 votes
X would equal -4 and for the point on a graph would be -4,0
User Tal Sahar
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories