Question

Find the area of a triangle whose base is 2√3 in. and height is 3√3 in.

6√3 in.²
9 in.²
18 in.²

Answer 1

area of a triangle = (b x h) /2
(2√3 × 3√3 )/2=
(2×3√3×3)/2 =
(6√9)/2 =
(6×3)/2 =
18/2 =
9 in²
Hope this helps

Answer 2

B. 9 inch²

Explanation:

We are given that,

Base of the triangle =
`2√(3)` inches

Height of the triangle =
`3√(3)` inches

Now, Area of the triangle =
`(1)/(2)(Base* Height)`

i.e. Area of the triangle =
`(1)/(2)(2√(3)* 3√(3))`

i.e. Area of the triangle =
`(1)/(2)(6* 3)`

i.e. Area of the triangle =
`(18)/(2)`

i.e. Area of the triangle = 9 inch²

Thus, the area of the triangle is 9 inch².

So, option B is correct.