Question

Find the quotient of the quantity negative 15 times x to the 2nd power times y to the 6th power plus 50 times x to the 4th power times y to the 3rd power minus 20 times x to the 2nd power times y all over 5 times x to the 2nd power times y.

−3y5 + 10x2y2 − 4
−15x2y6 + 50x4y3 − 4
3y5 + 10x2y2 − 4
−3xy5 + 10x2y2 − 4

Answer 1

Evaluate (-15*x^2*y^6+50*x^4*y^3-20*x^2*y)/(5*x^2*y)
In shorter words, its a.

Answer 2

`3y^(5)+10x^(2)y^(2)-4`

Explanation:

We have to find the quotient of the quantity

`(15x^(2)y^(6)+50x^(4)y^(3)-20x^(2)y)/(5x^(2)y)`

=
`(15x^(2)y^(6))/(5x^(2)y)+(50x^(4)y^(3))/(5x^(2)y)-(20x^(2)y)/(5x^(2)y)`

=
`3y^(5)+10x^(2)y^(2)-4`

Therefore,
`3y^(5)+10x^(2)y^(2)-4` is the quotient of the given expression.