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Part 1: Let f(x)=2x−1 and g(x)=−x2+x−3. Which equation shows h(x), where h(x)=f(x)⋅g(x)? h(x)=x2+x+3 h(x)=−x2+3x−4 h(x)=−2x3+x2−5x−3 h(x)=−2x3+3x2−7x+3 Part 2: Is function f even, odd, or neither? Part
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Sep 4, 2023
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Part 1: Let f(x)=2x−1 and g(x)=−x2+x−3. Which equation shows h(x), where h(x)=f(x)⋅g(x)?
h(x)=x2+x+3
h(x)=−x2+3x−4
h(x)=−2x3+x2−5x−3
h(x)=−2x3+3x2−7x+3
Part 2: Is function f even, odd, or neither?
Part 3: Is function g even, odd, or neither?
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Carrizo
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Part 1 answer is h(x) = -2x^3 + x^2 - 7x + 3
This is what I can help you with
Shomeax
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Sep 9, 2023
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