Question

Which expression can be used to find the zeros of the function f(x) = 4x2 + 2x - 12?​

Answer 1

x=-2 and x=-12

(-12,-2)

Answer 2

The zeros of the quadratic function are:

x = -2

x = 3/2

How to find the zeros?

The zeros are the values of x such that f(x) = 0

So we need to solve:

0 = 4x² + 2x - 12

Divide all by 2:

0 = (4x² + 2x - 12)/2

0 = 2x² + x - 6

The solutions are given by:

`x = (-1 \pm √(1^2 - 4*2*-6) )/(2*2) \\\\x = (-1 \pm7 )/(4)`

So the zeros are:

x = (-1 - 7)/4 = -2

x = (-1 + 7)/4 = 3/2