Question

5.An ice skater pushes against a wall with a force of 59 N. Ignoring friction, if the ice skater has

a total mass of 79 kg, what is the magnitude of his acceleration?
(A) 0.75 m/s2
(B) 1.3 m/s2
(C) 21 m/s2

Answer 1

Answer: (A) 0.75 m/s^2

Step-by-step explanation:

The Second Newton's law states that an object acquires acceleration when an external unbalanced net force is applied to it.

That acceleration is proportional to the net force and inversely proportional to the mass of the object.

It can be expressed with the formula:

`\displaystyle a=(F_n)/(m)`

Where

Fn = Net force

m = mass

The ice skater pushes against a wall with a force of 59 N. The wall returns the force and the skater now has a net force of Fn=59 N that makes him accelerate. Being m=79 kg the mass of the skater, the acceleration is:

`\displaystyle a=(59)/(79)`

`a = 0.75\ m/s^2`

Answer: (A) 0.75 m/s^2