Question

The vertices of △ABC are A(2, −3), B(−3, −5), and C(4, 1). If (x,y)--> (x-2, y+3), give the vertices of △A′B′C′.

Answer 1

A' = (0, 0)

B' = (-5, -2)

C' = (2, 4)

Explanation:

Vertices of triangle ABC:

• A = (2, -3)
• B = (-3, -5)
• C = (4, 1)

Given mapping rule:

(x, y) → (x - 2, y + 3)

This notation tells you that the x-coordinate is translated 2 units to the left, and the y-coordinate is translated 3 units up.

Substitute the coordinates of each point into the mapping rule to find the vertices of triangle A'B'C':

⇒ A' = (2 - 2, -3 + 3) = (0, 0)

⇒ B' = (-3 - 2, -5 + 3) = (-5, -2)

⇒ C' = (4 - 2, 1 + 3) = (2, 4)