Question

PLEASE HELP!!!!!!!!!!

<1 and <2 are supplementary. m<1 = 3x -4 and m<2 = 8x-14. Find the measure of each angle

a. m<1 = 130° , m<2 = 50°
b. m<1 = 50° , m<2 = 130°
c. m<1 = 110° , m<2 = 70°
d. m<1 = 70° , m<2 = 110°

Answer 1

(3x-4)+(8x-14)= 180

11x-18=180
+18 +18
----------------

11x=198
x=18



m<1= 3(18)-4
m<1= 50

m<2=8(18)-14
m<2=130

Answer is B.

Answer 2

The answer is the option b

`m<1=50\°`,
`m<2=130\°`

Explanation:

we know that

If angle 1 and angle 2 are supplementary

then

their sum is equal to
`180\°`

so

`(3x-4)\°+(8x-14)\°=180\°` -------> solve for x

`(11x-18)\°=180\°`

`11x=180\°+18\°`

`x=198\°/11=18\°`

`m<1=(3x-4)\°=(3*18-4)\°=50\°`

`m<2=(8x-14)\°=(8*18-14)\°=130\°`