What is the phase shift of y = –csc(3x − π)?

Question

asked Mar 19, 2018 140k views

2 Answers

Zakiyyah · Answer 1 · 2018-03-25T13:23:27+0000

Answer:

$(\pi)/(3)$

Explanation:

We are asked to find the phase shift of the function
$y=-\text{csc}(3x-\pi)$ .

We know that a function of form
$f(x)=a\cdot \text{csc}(bx-c)+d$ , where,

$\text{Period}=(2\pi)/(|b|)$ ,

$\text{Phase shift}=(c)/(b)$ ,

$\text{Vertical shift}=d$

Upon comparing our given function with standard function we can see that
a=-1 ,
b=3 and
$c=\pi$ .

$\text{Phase shift}=(\pi)/(3)$

Therefore, the phase shift for our given function is
$(\pi)/(3)$ .