Question

What is the phase shift of y = –csc(3x − π)?

Answer 1

The answer is pie over three

Answer 2

`(\pi)/(3)`

Explanation:

We are asked to find the phase shift of the function
`y=-\text{csc}(3x-\pi)`.

We know that a function of form
`f(x)=a\cdot \text{csc}(bx-c)+d`, where,

`\text{Period}=(2\pi)/(|b|)`,

`\text{Phase shift}=(c)/(b)`,

`\text{Vertical shift}=d`

Upon comparing our given function with standard function we can see that
`a=-1`,
`b=3` and
`c=\pi`.

`\text{Phase shift}=(\pi)/(3)`

Therefore, the phase shift for our given function is
`(\pi)/(3)`.