Question

- 3х +Зу = 12
у=х+ 4

How many solutions are there

Answer 1

Explanation:

As given system of linear equations,

• - 3х +Зу = 12
• у=х+ 4

Hence taking 1st equation ,

-3x+3y=12

-3(x-y)=12 ( common -3 )

• x-y=-4

now take 2nd equation ,

y=x+4

• y-x=4

Now add these two equations, we get

x-y+ y- x=-4+4

0x+0y=0

so it have infinite many solution because for any value L.H.S =R.H.S