Question

Find the range for the function K(n) = 2n^{2} when D = (-2,1,3)

Answer 1

The range will be the set of values taken on by the function
`K(n)` for each member of the domain set
`D`.

These values are


`K(-2)=2*(-2)^2=8`


`K(1)=2*1^2=2`


`K(3)=2*3^2=18`

So the range is the set
`R=\{2,8,18\}`.