117k views
1 vote
Find two consecutive even integers whose product is

1 Answer

5 votes
You can't find the precise integer without knowing what the product is - your question is incomplete - but you can find a general solution.

If
x is one of the integers, then the next even integer is given by
x+2. So if the product is
n, then you have


x(x+2)=k\implies x^2+2x=k\implies x^2+2x+1=k+1\implies (x+1)^2=k+1\implies x=-1\pm√(k+1)

Plug in
k and select the solution for
x that is an even integer.
User Pushparaj
by
7.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.