Question

Find two consecutive even integers whose product is

Answer 1

You can't find the precise integer without knowing what the product is - your question is incomplete - but you can find a general solution.

If
`x` is one of the integers, then the next even integer is given by
`x+2`. So if the product is
`n`, then you have


`x(x+2)=k\implies x^2+2x=k\implies x^2+2x+1=k+1\implies (x+1)^2=k+1\implies x=-1\pm√(k+1)`

Plug in
`k` and select the solution for
`x` that is an even integer.