Question

8. John has to hit a bottle with a ball to win a prize. He throws a 0.4 kg ball with a velocity of 18 m/s. It hits a 0.2 kg bottle, and the bottle flies forward at 25 m/s. How fast is the ball traveling after hitting the bottle?

Answer 1

I hope it helped you.

Answer 2

Answer: The velocity of the ball the ball after collision is 5.5 m/s.

Step-by-step explanation:

John hitting the bottle which is at rest means this is an Elastic collision.

Mass of the ball=
`M_1=0.4 kg`

Velocity of ball before collision =
`U_1=18m/s`

Velocity of ball after collision =
`V_1`

Mass of the bottle=
`M_2=0.2 kg`

Velocity of bottle before collision =
`U_2=0 m/s`(bottle is at at rest)

Velocity of bottle after collision =
`V_2=25 m/s`

`M_1V_1+M_2V_2=M_1U_1+M_2U_2`

`V_1=((0.4 kg* 18 m/s+0.2 kg* 0m/s)-0.2 kg* 25m/s)/(0.4)`

`V_1=5.5 m/s`

The velocity of the ball the ball after collision is 5.5 m/s.