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What is the y-value of the vertex of the function f(x) = –(x + 8)(x – 14)?

User Nuno Costa
by
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2 Answers

4 votes

Answer: d. 121 on edgen2021

Explanation:

User Bob Monteverde
by
8.5k points
3 votes

we have


f(x)=-(x+8)(x-14)

Convert to vertex form


f(x)=-(x+8)(x-14)\\f(x)=-( x^(2)-14x+8x-112) \\f(x)=-( x^(2)-6x-112)\\f(x)=-x^(2)+6x+112

we know that

the equation of a vertical parabola in vertex form is equal to


y=a(x-h)^(2) +k

where

(h,k) is the vertex


f(x)=-x^(2)+6x+112

Group terms that contain the same variable, and move the constant to the opposite side of the equation


f(x)-112=-(x^(2)-6x)

Complete the square. Remember to balance the equation by adding the same constants to each side


f(x)-112-9=-(x^(2)-6x+9)


f(x)-121=-(x^(2)-6x+9)

Rewrite as perfect squares


f(x)-121=-(x-3)^(2)


f(x)=-(x-3)^(2)+121

the vertex is the point
(3,121)

therefore

the answer is

The y-value of the vertex is
121

User Sid Heart
by
8.4k points

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