we have

Convert to vertex form

we know that
the equation of a vertical parabola in vertex form is equal to

where
(h,k) is the vertex

Group terms that contain the same variable, and move the constant to the opposite side of the equation

Complete the square. Remember to balance the equation by adding the same constants to each side


Rewrite as perfect squares


the vertex is the point

therefore
the answer is
The y-value of the vertex is
