Question

1. Calculate the mass of the product, if you started with 4 g of Zn and 3 g of H2CO3.

Zn + H2CO3
ZnCO2 + H2 * I’ll cash app for the right answer plus explanation”

Answer 1

6.07 g.

Step-by-step explanation:

Hello!

In this case, given the chemical reaction:

`Zn + H_2CO_3 \rightarrow ZnCO_3 + H_2`

We first need to compute the moles of each reactant considering their molar masses:

`n_(Zn)=4gZn*(1molZn)/(65.38 gZn) =0.0612molZn\\\\n_(H_2CO_3)=3gH_2CO_3*(1molH_2CO_3)/(62.03 gH_2CO_3) =0.0484molH_2CO_3`

Now, compute the mass of zinc carbonate yielded by each reactant in order to pick out the correct limiting reactant:

`n_(ZnCO3)^(by\ Zn) = 0.0612molZn*(1molZnCO3)/(1molZn)*(125.4 gZnCO3)/(1molZnCO3)=7.67gZnCO3 \\\\n_(ZnCO3)^(by\ H_2CO3) = 0.0484molH_2CO3*(1molZnCO3)/(1molH_2CO3)*(125.4 gZnCO3)/(1molZnCO3)=6.07gZnCO3`

Thus, we conclude carbonic acid is the limiting reactant as it produces the fewest grams of product and therefore the yielded mass of zinc carbonate product 6.07 g.

Best regards.