Question

Find the area of the surface of the part of y=4x+z^2 that lies between the planes

Answer 1

Y) Recorder
`4x` and
`z^2`


`y=z^2+4x`

X)Solve for
`x` by simplifying both sides of the equation, then isolate the variable


`x=- ( z^(2) )/(4)+ (y)/(4)`

Z)Take the root of both sides and solve.


`z= √(-4x+y), - √(-4x+y)`