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Find the area of the surface of the part of y=4x+z^2 that lies between the planes

User Pashec
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1 Answer

4 votes
Y) Recorder
4x and
z^2


y=z^2+4x

X)Solve for
x by simplifying both sides of the equation, then isolate the variable


x=- ( z^(2) )/(4)+ (y)/(4)

Z)Take the root of both sides and solve.


z= √(-4x+y), - √(-4x+y)


User Bhavik Goyal
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6.0k points