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Find the total area of the regular pyramid.

Find the total area of the regular pyramid.-example-1

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check the picture below.

notice, the base of the "square" pyramid, is a square, and it has 4 triangular faces with a base of 2, and a height of √(10).

so the total surface area is the area of the base plus all 4 triangular faces' areas.


\bf \stackrel{\textit{squarish base}}{(2\cdot 2)}~~~~+~~~~\stackrel{\textit{4 triangular faces}}{4\left[ \cfrac{1}{2}(2)(√(10)) \right]}
Find the total area of the regular pyramid.-example-1
User Bfcm
by
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6 votes

Answer:

Area of the regular pyramid = 16.64 square units.

Explanation:

Given : Regular pyramid .

To find: Find the total area of the regular pyramid.

Solution : We have given that regular pyramid.

Area = 4 ( area of triangle ) + area of base .

Area of the regular pyramid = 4 (
(1)/(2) * base * height + side * side.

Area of the regular pyramid =
4((1)/(2)* 2* √(10)  + 2*2

Area of the regular pyramid =
4( √(10) ) + 4

Area of the regular pyramid = (4
( √(10) ) \+\ 1.

Area of the regular pyramid = 16.64 square units.

Therefore, Area of the regular pyramid = 16.64 square units.

User Linga
by
7.8k points

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