Question

What is the volume of 12.0 g of cl2 gas at stp

Answer 1

Hi I think I might know the answer to your question it is pretty tricky though!
Chlorine Gas = 70.8 grams/moles
Moles of Chlorine Gas = 57.8/70.8 = 0.816 mol
Volume Gas at STP = 22.4 L/mol
Volume of Chlorine Gas = .816*22.4=18.22 Litters
I hoped that helps if not so sorry!

Answer 2

`V=3.79L`

Step-by-step explanation:

Hello,

In this case, we are talking about an ideal gas problem in which 12.0 g of chlorine gas is at standard both pressure (1atm) and temperature (0°C), therefore, to compute the corresponding volume, one applies the ideal gas law, then converts from grams to moles considering the diatomic chlorine and subsequently solves for volume as shown below:

`PV=nRT\\V=(nRT)/(P)=(12.0gCl_2*(1molCl_2)/(70.9gCl_2) *0.082 (atm*L)/(mol*K) * 273.15K)/(1atm)  \\V=3.79L`

Best regards.