138k views
2 votes
Write in slope-intercept form an equation of the line that passes through the given points.

(−1, −1), (1, 5)

2 Answers

3 votes

Answer: y=3x+2

Step-by-step explanation:

Slope-intercept form: →
y=mx+b

m: represents the slope and is constant.

b: represents the y-intercept.

The y-intercept is the point on a graph at which the graph crosses the y-axis.

Used rise/run.


m=(rise)/(run)


rise=y^2-y^1


run=x^2-x^1


(x^1,y^1)=(-1,-1)


(x^2,y^2)=(1,5)


rise=y^2-y^1=5-(-1)


run=x^2-x^1=1-(-1)


(5-(-1))/(1-(-1))= (6)/(2)=3*2=6=3


5-3(1)=2(1)=2*1=2

Hope this helps!

Thanks!

User Baz
by
8.3k points
3 votes
Slope-intercept form uses the following equation: y = mx + b. m is the slope, and b is the y-intercept of the equation.

Use the following formula to figure out the rise and run of these points:


(y2 - y1)/(x2 - x1)

Plug the x and y values into the equation to determine the slope.


(5 - (-1))/(1 - (-1)) =
(6)/(2) = 3

Use the slope to find the y-intercept of the equation. You can find this by taking a point and using addition/subtraction and multiplication.

Taking the point (1,5), you can do the following:

5 - 3(1) = 2

The final equation is y = 3x + 2.

User Dvdgsng
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories