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Ljmelgui · Answer 1 · 2019-05-12T11:56:53+0000

The frequency of the bug is given by the number of revolutions completed per second:

f= (N)/(t)= (12 rev)/(1 s)=12 s^(-1) = 12 Hz

The angular velocity is related to the frequency by the following relationship:

$\omega=2 \pi f$
And using f=12 Hz, we can find the angular velocity of the bug:

$\omega = 2 \pi (12 Hz)=75.36 rad/s$

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