Question

A small bug is spinning in a circle. The bug is spinning 12 times a second. What is the angular velocity of the bug?

Answer 1

The frequency of the bug is given by the number of revolutions completed per second:

`f= (N)/(t)= (12 rev)/(1 s)=12 s^(-1) = 12 Hz`

The angular velocity is related to the frequency by the following relationship:

`\omega=2 \pi f`
And using f=12 Hz, we can find the angular velocity of the bug:

`\omega = 2 \pi (12 Hz)=75.36 rad/s`