Question

Given a possible triangle ABC with a=5,b=11,and a=23, find a possible value for

Answer 1

The question is as follow:

Given a possible triangle ABC with a=5, b=11, and A=23 degrees, find a possible value for angle B. Round to the nearest tenth.
A. 10.2° B. 11.2° C. 59.3° D. no solution
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a = 5 , b = 11 , and ∠A = 23°

By applying the Law of Sines:

`(sin \ A)/(a) = (sin \ B)/(b)`


`(sin \ 23)/(5) = (sin \ B)/(11)`

∴ sin B = 11* (sin 23°)/5 ≈ 0.8596

∴ ∠B =
`sin^(-1) 0.8596` ≈ 59.3°

∴ The correct choice is option (C)
C. 59.3°