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A hot heater measures 20 in diameter. What is the area of a metal base for the water heater, assuming a 2 inch overhang around the base of the water heater

User Jivan
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1 Answer

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The diameter of the heater=20 in
Diameter of the heater and the overhang=20+4=24 in
the area of the base will therefore be:
A=πr²
A=π(24/2)²
A=144π in²
A~452.39 in²
User Nxtwrld
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