Question

Anthony is standing on the top of a building 10 m high holding a 7 kg

bowling ball. Mildred dug a 2-m-deep hole next to the base of the
building. What is the gravitational potential energy of the bowling ball
relative to the bottom of the hole?
I reallly need help!!

Answer 1

The gravitational potential energy of the 7kg bowling ball, relative to the bottom of the 2-meter-deep hole, is calculated using the formula GPE = mgh and it totals 823.32 Joules.

Step-by-step explanation:

To calculate the gravitational potential energy (GPE) of the 7kg bowling ball relative to the bottom of the 2-meter-deep hole next to the building, we first need to determine the total height from the bottom of the hole to Anthony's position. This will be the height of the building plus the depth of the hole, which is 10m + 2m = 12m. We then use the formula for gravitational potential energy:

GPE = mgh

Where:

• m is the mass of the bowling ball (7kg)

• g is the acceleration due to gravity (9.81 m/s²)

• h is the height above the reference point (12 m)

Plugging in the numbers:

GPE = 7 kg * 9.81 m/s² * 12 m

Plugging in the numbers:

GPE = 7 kg * 9.81 m/s² * 12 m

GPE = 823.32 J (Joules)

So, the gravitational potential energy of the bowling ball relative to the bottom of the hole is 823.32 Joules.