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3 votes
The population P of a colony of 3600 bacteria at time t minutes can be modeled by the function P(x) = 3600(2)^t/73. How long does it take the population (in hours) to reach 1,792,000?

2 Answers

4 votes
It takes 10.9 hours.

We set the equation equal to 1792000:


1792000=3600(2)^{(t)/(73)}

Divide both sides by 3600:

(1792000)/(3600)=\frac{3600(2)^{(t)/(73)}}{3600} \\ \\(4480)/(9)=2^{(t)/(73)}

We will use logarithms to solve this:

\log_2{(4480)/(9)}=(t)/(73)

Multiply both sides by 73:

73\log_2{(4480)/(9)}=t \\ \\654.03=t

This is in minutes; to convert to hours, divide by 60:
654.03/60 = 10.9
4 votes
The answer is: 10.90 hours

Step-by-step explanation:
Please see the image attached!
The population P of a colony of 3600 bacteria at time t minutes can be modeled by-example-1
User Drootang
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