97.8k views
1 vote
(z-2) (z+6) Multiplying polynomials

2 Answers

4 votes


z2-z-6=0

Two solutions were found :

z = 3
z = -2
Reformatting the input :

Changes made to your input should not affect the solution:

(1): "z2" was replaced by "z^2".

Step by step solution :

Step 1 :

Trying to factor by splitting the middle term

1.1 Factoring z2-z-6

The first term is, z2 its coefficient is 1 .
The middle term is, -z its coefficient is -1 .
The last term, "the constant", is -6

Step-1 : Multiply the coefficient of the first term by the constant 1 • -6 = -6

Step-2 : Find two factors of -6 whose sum equals the coefficient of the middle term, which is -1 .

-6 + 1 = -5
-3 + 2 = -1 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and 2
z2 - 3z + 2z - 6

Step-4 : Add up the first 2 terms, pulling out like factors :
z • (z-3)
Add up the last 2 terms, pulling out common factors :
2 • (z-3)
Step-5 : Add up the four terms of step 4 :
(z+2) • (z-3)
Which is the desired factorization

Equation at the end of step 1 :

(z + 2) • (z - 3) = 0
Step 2 :

Theory - Roots of a product :

2.1 A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

2.2 Solve : z+2 = 0

Subtract 2 from both sides of the equation :
z = -2

Solving a Single Variable Equation :

2.3 Solve : z-3 = 0

Add 3 to both sides of the equation :
z = 3

User MatG
by
8.4k points
7 votes

x^(2) +6z-2z+12 = x^(2) +4z+12
User Dervin Thunk
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories