Question

Simplify quantity 18 x minus 6 over 9 x to the fifth power all over quantity 15 x plus 5 over 21 x squared

Answer 1

Answer:
`(98(3x-1))/(3^7.5x^3(3x+1))`

Explanation:

Given expression,
`(18x-6/(9x)^5)/(15x+5/(21)^2)`

=
`((18x-6)* 21^2x^2)/(9^5.x^5* (15x+5))`

=
`((18x-6).7^2)/(x^3.9^4(15x+5))`

=
`(2* 7^2(3x-1))/(3^7x^3(15x+5))`

=
`(2* 49(3x-1))/(3^7x^3.5(3x+1))`

=
`(98(3x-1))/(3^7.5x^3(3x+1))`

Answer 2

Going off of your description, I got and solved this equation:


`( (18x-6)/(9x^(5) ))/( (15x+5)/(21x^(2) ) )`

I simplified it to:


`( (6(3x-1))/(9x^(5)) )/( (5(3x+1))/(21 x^(2) ) )`

I then simplified again and flipped the second fraction to get a multiplication problem:


`(2(3x-1))/(3 x^(5) )( (21 x^(2) )/(5(3x+1))`

Which then simplifies to your answer:


`(14(3x-1))/(5 x^(3)(3x+1))`