Question

Solution A is 30% alcohol and solution B is 60% alcohol. How much of each is needed to make 80 liters of a solution that is 45% alcohol?

Answer 1

To solve this problem, set up a system of two equations and solve for the unknowns. The equations are x + y = 80 and 0.30x + 0.60y = 36.

Step-by-step explanation:

To solve this problem, you can set up a system of two equations. Let x represent the volume of solution A and y represent the volume of solution B. We can create the following equations:

x + y = 80 (equation 1)

0.30x + 0.60y = 0.45(80) (equation 2)

Simplifying equation 2, we get:

0.30x + 0.60y = 36

Multiplying both sides of equation 2 by 100 to eliminate decimals, we get:

30x + 60y = 3600

You can then solve this system of equations to find the values of x and y, which will give you the amounts of solution A and solution B needed to make the desired solution.

Answer 2

We need 80 liters of 45% alcohol
We have 30% alcohol and 60% alcohol.
This is relatively easy. We need equal amounts of each.
There fore we mix 40 liters of 30% alcohol and 40 liters of 60% alcohol.