Question

Hi! What is y = x^2 -4x +5 vertex form? Please explain how you got this answer. Thanks! :)

Answer 1

you need to do y=a(x-h)2 +k  but your vertex is ( 2,1)

Answer 2

`{x}^(2) - 4x + 5 = 0 \\ {x}^(2) - 4x = - 5 \\ \\ { ((b)/(2) )}^(2) = ( ( - 4)/(2) ) = ( { - 2})^(2) = 4 \\ {x}^(2) - 4x + 4 = - 5 + 4 \\ {(x - 2)}^(2) = - 1 \\ {(x - 2)}^(2) + 1`
The last line is in vertex form, and can see the vertex is located at (2,1).